Lionheart

So what does & suggest by opportunity? I am aware that & means ‘and’, but amp has wondering.

Where 3 5 & offers 1

The bits in each place in the 1st quantity (chr) must match bits in each place into the number that is second. Right Here just the people in red.

One other place either have actually 0 and 0 equals 0 or 1 and 0 equals 0. Nevertheless the position that is last 1 and 1 equals 1.

Lionheart

Do you want more explanation – or can you simply instead skip it.

Do you encounter this in another of ACES guages and desired to discover how it worked?

Think about it you really need to have counted in binary as a young child

Zero one ten eleven one hundred a hundred and another one hundred and ten one hundred and eleven.

I want to explain or even to you.

No https://datingmentor.org/beautifulpeople-review/ No make him stop. We’ll talk, We’ll talk

FelixFFDS

Ron – i might have understood exactly what the AND operator designed – a time that is long – in university.

Therefore making use of your instance, 3,5 OR gives me personally “6”?

N4gix

Hey dudes, So what does & suggest by possibility? I am aware that & means ‘and’, but amp has wondering. Many thanks,

While Ron is “technically proper, ” i am let’s assume that you just desired to know the following:

& is simply the way that is”full of writing the “&” sign.

. Exactly like &gt: may be the way that is”full of composing “”.

(Hint: the icon is known as an “ampersand” or “amp” for short! )

In FS XML syntax, it’s utilized similar to this:

&& is the identical as &&amp is equivalent to and

I recently explained this in another post in regards to a week ago.

You did XOR – exclusive OR

The bits are compared by you vertically – in my own examples

The picture is got by you.

A 1 OR 0 is 1 A 0 OR 1 is 1 A 1 OR 1 is 1 A 0 OR 0 is 0

A 1 OR 0 is 1 A 0 OR 1 is 1 A 1 OR 1 is 0

N4gix

+ (binary operator): adds the past two stack entries – (binary operator): subtracts the very last two stack entries * (binary operator): multiplies the final two stack entries / (binary operator): divides the very last two stack entries percent (binary operator): rest divides the final two stack entries /-/ (unary operator): reverses indication of final stack entry — (unary operator): decrements last stack entry ++ (unary operator): increments final stack entry

(binary operator): ”” offers 1 if final stack entry is higher than forelast stack entry (binary operator): ” &gt=; (binary operator): ”=” provides 1 if final stack entry is higher than or add up to forelast stack entry &lt=; (binary operator): ” == (binary operator): offers 1 if both final final stack entries are equal && (binary operator): ”&&” rational AND, if both final stack entries are 1 provides 1 otherwise 0 || (binary operator): logical OR, if a person associated with final stack entries is 1 outcome is 1 otherwise 0! (unary operator): rational never, toggles last stack entry from 1 to 0 or 0 to at least one? (ternary operator): ”short if-statement”, in the event that final entry is 1, the forelast entry is employed, else the fore-forelast ( or the other way round. Test it, view it)

& (binary operator): ”&” bitwise AND | (binary operator): bitwise OR

(unary operator): bitwise NOT, toggles all bits (binary operator): ” (binary operator): ”” change bits of forelast stack entry by final stack actions off to the right

D: duplicates last stack entry r: swaps final two stack entries s0, s1, s2.: shops stack that is last in storage for later use sp0, sp1, sp2.: (presumably) equivalent as above l0, l1, l2.: lots value from storage space and places together with stack

(unary operator): provides next smallest integer dnor (unary operator): normalizes degrees (all values are ”wrapped across the group” to 0°-360°) rnor (unary operator): normalizes radians (all values are ”wrapped around the circle” to 0-2p) (NOTE: does not work too reliable) dgrd (unary operator): converts levels to radians (also rddg available? ) pi: places p over the top of stack atg2 (binary operator): gives atan2 in radians (other trigonometric functions? Sin, cos, tg? Other functions? Sqrt, ln? ) maximum (binary operator): provides the greater of final two stack entries min (binary operator): provides the smaller of final two stack entries

Other people: if if final stack entry is 1, the rule within the brackets is performed (remember that there isn’t any SPACE between ”if” and ”<” but one after it and at least one SPACE before ”>”) if < . >els if final stack entry is 1, the rule in the brackets is executed, else the rule within the 2nd pair of brackets ( simply just take also care to where SPACEs are permitted and where perhaps perhaps maybe not) quit renders the execution instantly, last stack entry can be used for further purposes instance difficult to explain, consequently an illustration:

30 25 20 10 5 1 0 7 (A: Flaps handle index, quantity) situation

The figures 30 25 20 10 5 1 0 are pressed along the stack, 7 states exactly exactly how entries that are much in line with the consequence of (A: Flaps handle index, quantity) ”case” extracts one of many seven figures. If (A: Flaps handle index, number) is 0 – 0, 1-1, 2-5. 6-30.